28x^2-5=-5x^2-127

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Solution for 28x^2-5=-5x^2-127 equation: 



28x^2-5=-5x^2-127

We move all terms to the left:

28x^2-5-(-5x^2-127)=0

We get rid of parentheses

28x^2+5x^2+127-5=0

We add all the numbers together, and all the variables

33x^2+122=0

a = 33; b = 0; c = +122;
Δ = b2-4ac
Δ = 02-4·33·122
Δ = -16104
Delta is less than zero, so there is no solution for the equation

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